Now that Tom has been introduced to FEA, swing simulations, aerodynamics, and other club modeling software, he has to apply these and put everything together. He spent this last week analyzing his current set of clubs along with their performance, then predicting the ideal set of clubs for him. He not only has to figure out what clubs will be right for him, but he has to quantify how much improvement there should be and why. He will then present his findings where his decisions will be scrutinized by the rest of us in R & D. Here are Tom’s thoughts on his report thus far.

*So for the last week or so, I felt like I was back in school. Writing an extremely long report (49 pages) and preparing an equally as long PowerPoint presentation. I am slightly nervous because this project is infamous around all departments within CG and I can already see my fellow R&D members preparing to present me with an onslaught of questions regarding my assumptions and conclusions. Alex in particular has been on cloud 9 for the last few weeks, since this will be his first opportunity to be in the audience for this presentation. However, I think I’m pretty well prepared. Brian and Alex have been invaluable help with this project, as they have been instructing me on what causes what and why – so I assume I can always blame them if I get something wrong. *

* **Well today I throw myself to the wolves…so it has been nice knowing all of you. However, if I get lucky and make it through this, I get to play these clubs on Wednesday at the department golf outing. Wish me luck.*

Tom seems to know his stuff, so I’m sure he’ll do more than just make it through the presentation (at least I hope so because I helped train him). We’ll let you know next week how he did and he can tell you about his new set of clubs.

Congratulations to Todd for winning last week’s logic problem. See all the creative responses at http://blog.clevelandgolf.com/?p=655. Once again, everyone who posted an answer got entered into a drawing for a “First Run” CG15 Wedge. Below is this week’s logic problem.

The Clock: Assume the hour hand continuously turns, and the minute hand discretely jumps from one tick mark to the next each minute. At what times are the hour and minute hands exactly 1 tick mark apart? For example (and shown below), at 6:30, they are 2.5 tick marks apart.

time to golf

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11.59–

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11:59 and 12:01

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Assuming that we are only considering whole minutes here (ie. dont count when the minute hand jumps between minutes) you have 2:12 and 9:48, am and pm.

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Since the hour hand takes 12 minutes to move on tick mark and assuming the minute hand has to be lined up exactly on a tick mark, 6:12 am or pm At 9:48 the minute hand and the hour hand are exactly lined up.

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Sorry typo in my reposnse – should have read 2:12 not 6:12

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2:12 and 9:48 are the times that the hour and minute hands will be 1 tick apart.

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2:13 AND 9:49

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The answer has been given but I’ll enter: 2:12 & 9:48

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I want those CG 15s!

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12:01, 2:12, 3:15, 4:21, 4:23, 5:26, 6:31 7:37, 7:39, 8:42, 9:48, 9:50, 10:56, 11:59 am and pm

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none if that effin clock is broken, now Gimme CG15′s please!

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The answer is 2:12 and 9:48 they will be a tic apart

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I guess it is splitting hairs and based on your interpretation of the question, but I am going wth 2:11 and 9:47

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